Python, inspect - Get full caller name (package.module.function).

def caller_name(skip=2):
    """Get a name of a caller in the format module.class.method

       `skip` specifies how many levels of stack to skip while getting caller
       name. skip=1 means "who calls me", skip=2 "who calls my caller" etc.

       An empty string is returned if skipped levels exceed stack height
    from inspect import stack, getmodule

    stack = stack()
    start = 0 + skip
    if len(stack) < start + 1:
        return ''
    parentframe = stack[start][0]

    name = []
    module = getmodule(parentframe)
    # `modname` can be None when frame is executed directly in console
    # TODO(techtonik): consider using __main__
    if module:
    # detect classname
    if 'self' in parentframe.f_locals:
        # I don't know any way to detect call from the object method
        # XXX: there seems to be no way to detect static method call - it will
        #      be just a function call
    codename = parentframe.f_code.co_name
    if codename != '<module>':  # top level usually
        name.append(codename)  # function or a method
    del parentframe
    return ".".join(name)